2x^2-102x+672=0

Solution for 2x^2-102x+672=0 equation:

2x^2-102x+672=0

a = 2; b = -102; c = +672;
Δ = b2-4ac
Δ = -1022-4·2·672
Δ = 5028
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5028}=\sqrt{4*1257}=\sqrt{4}*\sqrt{1257}=2\sqrt{1257}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-2\sqrt{1257}}{2*2}=\frac{102-2\sqrt{1257}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+2\sqrt{1257}}{2*2}=\frac{102+2\sqrt{1257}}{4}
$